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memmove

Usage

   #include <string.h>

   void *memmove(void *buf1,const void *buf2, size_t count);

   ANSI

Description

   memmove copies the number of characters specified in count from buf2 to
   buf1. buf1 is returned.  memmove, slower than memcpy, can handle
   overlapping moves.

Example 

   See The Memory package

Return Value

   memmove returns buf1.

See Also

   memcpy, strcmp, strcat, strset, strchr