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I'm getting an IE 999!  Why?

An IE 999 usually occurs when a referenced function is not linked in.

The most common cause of this error is creating indexes in one EXE and using
them in another.

For example, suppose you use DESCEND() in one of your index expressions.  If
you bring this index into use in another program where it's not explicitly
referenced, DESCEND() was not necessarily linked in.  This can cause an IE
999.

To resolve this problem add the following line to one of the PRG's that is
part of your application:

    EXTERN DESCEND